![If the sum of n terms of a G.P. (with common ratio r ) beginning with the p^th term is k times the sum of an equal number of terms of the If the sum of n terms of a G.P. (with common ratio r ) beginning with the p^th term is k times the sum of an equal number of terms of the](https://dwes9vv9u0550.cloudfront.net/images/7356448/a37ea959-3e4d-4ab9-b769-68df46137f0c.jpg)
If the sum of n terms of a G.P. (with common ratio r ) beginning with the p^th term is k times the sum of an equal number of terms of the
![Show that the Ratio of the Sum of First N Terms of a Geometric Progression. to the Sum of Terms from (N + 1)^(Th) " to "(2n)^(Th) " Term is " 1/R^N - Show that the Ratio of the Sum of First N Terms of a Geometric Progression. to the Sum of Terms from (N + 1)^(Th) " to "(2n)^(Th) " Term is " 1/R^N -](https://www.shaalaa.com/images/_4:62ab8ae07fad48b3aa5d56780d3b76d0.png)
Show that the Ratio of the Sum of First N Terms of a Geometric Progression. to the Sum of Terms from (N + 1)^(Th) " to "(2n)^(Th) " Term is " 1/R^N -
The sum of 7 numbers in a geometric progression is 108 .the sum of their reciprokals is 12 .the geometric mean of 3 middle terms of geometric progression is?
If sum of the n terms of a G.P be S, their product P and the sum of their reciprocals R, the prove that P^2 = (S/R)^n - Sarthaks eConnect | Largest
![The sum of the first three terms of a G.p is 13/12 and their product is -1 - Home Work Help - Learn CBSE Forum The sum of the first three terms of a G.p is 13/12 and their product is -1 - Home Work Help - Learn CBSE Forum](https://ask.learncbse.in/uploads/db3785/original/3X/5/6/56b9e5e462427014a272a56847810eae4cb5cb51.png)